This isn't tertiary it's secondary as stated and labelled at 5:59 , since yes it's connected to two other carbons. 

What Ari was referring to was that Elimination reactions, both E1 and E2, favor tertiary and secondary alkyl halides. The wedged doesn't do anything here it's just showing stereochemistry which doesn't matter here since elimination just changes the product to an alkene. The stereochemistry (wedged or dashed) matters when we are doing substitution reactions since we will either have inversion (SN2)  or both inversion and retention (racemization, SN1). 

The end product is yes, it is also written on the slide in the black text for reference. 

Ashley Wampler Yes this is still an acid-catayzed tautomerization.

At 0:59 it shows the mechanism then at 4:41 it shows another example of the mechanism. 

Our team just emailed you. The video you are looking for is the following:

Yes the formation of cyclopropanes is the same thing as cyclopropanation. Your lecture notes just show a more complex structure. But the overall concept is still the same, we start with an alkene and use a carbene to form the cyclopropane. 

At this time we don't have downloads of these reaction summaries but you can find the video review and reaction summaries of several functional groups here in the below video. Check the timestamps in the description for each reaction summary.

That would still be correct. Either answer, with or without the Hydrogens would be accepted.

For the study with us series, we do not have an answer key because the answers are shown in the video. You'll find timestamps to each question/answer in the description of this video. The purpose of this was so that students would watch the full video because there are several different tips/tricks Melissa shows throughout the video and we don't want you to miss that. 

kay Luffman No worries! Happy to hear it makes sense :)