For task at 23:46, is my drawing right? could i draw it this way? the aldol and E1CB product. Chemmunity Team

Could one draw the final product of 10:36 like this? (picture attached) 

Question, is my structure right drawn? Chemmunity Team (sorry for alot of questions).

Question, cause it is said that in aldol reaction, we need 2 alfa hydrogen for -OH to attack. But what if we have a structure like this ( se picture attached). Like we have 2 hydrogen on one side, and 3 hydrogen on the other side. Or like 2 hydrogen on both side ? which side to we attack to form the enolate? is one side more prefered then the other? 

Task 10:39 could i draw it this way? (see picture attached). And is my reversed aldol reaction and product right?  Chemmunity Team

If one got the question on the exam "draw the reversed product of 07:05". Is it right if i drew it like this? see picture attached. Chemmunity Team

Hi, task 07:05 i drew it like this (the final product) is it right? I learned this trick to number it by 1, 2 and 3. So number 1 is the purple dot (carbon with the karbonyl). 2 is the yellow dot (alfa carbon) and 3 is the carbon that we gonna attack (beta carbon) - brown dot. Is my structure right? Chemmunity Team

Sarah - Subject Expert Thanks alot, could you dobble check if my drawings are right? especially where i have marked it in blue, (when gingard attacks formalaldehyd) > are my number of carbons right when forming the primary alcohol?

Sarah - Subject Expert So my answer is wrong? but I don't understand. Because in the problem below (the first one), you said that my answer is correct like that? (is that right)?

But is my answer in the second problem wrong? don't understand (look at the picture in this comment).

Why is the first awnser right?, but the second one wrong? please expalin..

06:37, it says we can only use CH3X or primary alkyl halide, when we want to attach it to the enolate nuc site. Sooo if one used for example MEOH, wouldnt that work? like from enolate >>> ether? (attaching OME) ? see picture attached: Chemmunity Team