Cooper McIntyre - Instructor Thank you! I'm also confused at 15:30. But is it lower pka means higher acidity (and lower pH)?

At 7:55 I got a little confused, doesn't a lower pH increase acidity? Like a pH of 1 is more acidic than pH of 3?

at 8:25 are we showing 2 products because both carbons are secondary? if the carbons were differently substituted, would i still show 2 products, or would i only pick the one with the carbocation on the most substituted carbon?

At 8:15 would there be cis/trans products since the only atoms attached to the beta carbon are 2 Hydrogens? resulting in 3 products instead of 2?

At 48:00 why were the hydrogrens drawn and wedge/dash and not two regular bonds? Since when there are two hydrogens on the same beta carbon we get trans and cis alkenes

At 11:16 did Melissa mean 1 ethyl + 1 methyl? Instead of 1 ethyl + 2 methyls?

at 18:20 could it be a tiebreaker knowing that the example w the extra O would mean the whole molecule is more electronegative, which would mean a stronger acid?

Also, at 22:30, can we look at other parts of the molecule (not just at the C where the given H is) to check for hybridization? I noticed sp3 in the less acidic molecule where there's sp2 in the more acidic.

At 14:35 how do we know that C doesn't have 4 Hydrogens it's bonded to and that would give it a -1 formal charge, rather than 2 Hydrogens and a lone pair?

but don't we know at 17:38 that we can make 4 bonds because the highest energy level we see on the electron configuration of C is 2, and we add up the exponents 2 + 2 = 4 VE so we know it can make 4 bonds that way? Why is she saying it's confusing that the 2 unpaired electrons on the hybrid orbitals diagram tell us C makes only 2 bonds when we were taught how to know there's actually 4 VE?

Jen - Subject Expert I don't get why this would be wrong, since O is the most electronegative, isn't it okay for it to have a formal charge of -1 like you drew?